240.Search a 2D Matrix II¶
Tags: Medium
Binary Search
Divide and Conquer
Links: https://leetcode.com/problems/search-a-2d-matrix-ii/
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted in ascending from left to right.
- Integers in each column are sorted in ascending from top to bottom.
Example:
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5
, return true
.
Given target = 20
, return false
.
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
if (matrix.empty() || matrix[0].empty()) return false;
int m = matrix.size(), n = matrix[0].size();
int row = m - 1, col = 0;
while (row >= 0 && col < n) {
if (matrix[row][col] == target) return true;
else if (matrix[row][col] < target) ++col;
else --row;
}
return false;
}
};
从左下角往右上角搜索,很常见的思路。