1009.Complement of Base 10 Integer¶
Tags: Easy
Bit Manipulation
Links: https://leetcode.com/problems/complement-of-base-10-integer/
Every non-negative integer N
has a binary representation. For example, 5
can be represented as "101"
in binary, 11
as "1011"
in binary, and so on. Note that except for N = 0
, there are no leading zeroes in any binary representation.
The complement of a binary representation is the number in binary you get when changing every 1
to a 0
and 0
to a 1
. For example, the complement of "101"
in binary is "010"
in binary.
For a given number N
in base-10, return the complement of it's binary representation as a base-10 integer.
Example 1:
Input: 5
Output: 2
Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10.
Example 2:
Input: 7
Output: 0
Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10.
Example 3:
Input: 10
Output: 5
Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10.
Note:
0 <= N < 10^9
- This question is the same as 476: https://leetcode.com/problems/number-complement/
class Solution {
public:
int bitwiseComplement(int N) {
std::ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
if (N == 0) return 1;
unsigned int mask = INT_MAX;
while (mask & N) mask <<= 1;
return (~N) & (~mask);
}
};
按位取反很自然的联想到运算符~
,但是如果能够固定数量的按位取反,其实可以考虑利用INT_MAX
的移位操作,不断左移,直到和num
的与运算为0,那么就可以确定需要按位取反的有多少位了,注意存在输入为0的情形。另外要用unsigned int
类型。